Gujarati
Hindi
5.Work, Energy, Power and Collision
normal

Power applied to a particle varies with time as $P = (4t^3 -5t + 2)\,watt$, where $t$ is in  second. Find the change is its $K.E.$ between time $t = 2$ and $t = 4 \,sec.$ ............... $\mathrm{J}$

A

$212$

B

$213$

C

$214$

D

$215$

Solution

Hint. $=\frac{d k}{d t}=4 t^{3}-5 t+2$

So change in $K.E.$ will be $214 \,J.$

Standard 11
Physics

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